Estimation of difference among population proportions , Mathematics

Estimation of difference among population proportions

Assume the two proportions be described by P1 and P2, respectively,Then the difference absolute between the two proportions is described by (P1 - P2)

The standard error is described by:-

S(P1 - P2) = √{(pq/n1) + (pq/n2)}  =   where p = (p1n1 + p2n2)/(n1 + n1)  and q = 1 - p

Then described the confidence level, the confidence interval among the two population proportions is described by

(P1 - P2) ± Confidence level S(P1 - P2)

= (P1 - P2) ± Z  √{(pq/n1) + (pq/n2)} 

Whereas P = (p1n1 + p2n2)/(n1 + n1)  always remember to convert P1 and P2 to P.

 

Posted Date: 2/19/2013 12:35:00 AM | Location : United States







Related Discussions:- Estimation of difference among population proportions , Assignment Help, Ask Question on Estimation of difference among population proportions , Get Answer, Expert's Help, Estimation of difference among population proportions Discussions

Write discussion on Estimation of difference among population proportions
Your posts are moderated
Related Questions
Cartesian product - situations in which the total number of ordered pairs (or triples, or ...) are do be found. (e.g., if Hari makes 'dosas' of 3 different sizes, with 4 different

Derivatives of Hyperbolic Functions : The last set of functions which we're going to be looking at is the hyperbolic functions.  In several physical situations combinations of e

Equation for the given intervaks in the intervaks, giving ypout answer correct to 0.1 1.sin x = 0.8 0 2. cos x =-0.3 -180 3.4cos theta- cos theta=2 0 4. 10tan theta+3=0 0

(1) Show that the conclusion of Egroff's theorem can fail if the measure of the domain E is not finite. (2) Extend the Lusin's Theorem to the case when the measure of the domain E

Solve the following: Line Bearings Distance a. N 15 E 4km b. S 10 E ? c. N 80 W ?


∫1/sin2x dx = ∫cosec2x dx = 1/2 log[cosec2x - cot2x] + c = 1/2 log[tan x] + c Detailed derivation of ∫cosec x dx = ∫cosec x(cosec x - cot x)/(cosec x - cot x) dx = ∫(cosec 2 x

A pair of pants costs $24. The cost was decreased by 8%. What is the new cost of the pants? If the cost of the pants is decreased by 8%, the cost of the pants is 92 percent of


X^2 – y^2 – 2y - 1