Perpendicular to the line given by 10 y + 3x= -2

For this part we desire the line to be perpendicular to 10 y + 3x= -2 & so we know we can determine the new slope as follows,

m ₂ =-=1/(-3/10)=10/3

Then, just as we did in the earlier part we can employ the point-slope form of the line to obtain the equation of the new line.  Here it is,

y=2+(10/3)(x-8)

=2+(10/3)x-(80/3)

y =(10/3)x-74/3

 

Posted Date: 4/6/2013 6:09:02 AM | Location : United States

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