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Perpendicular to the line given by 10 y + 3x= -2
For this part we desire the line to be perpendicular to 10 y + 3x= -2 & so we know we can determine the new slope as follows,
m 2 =-=1/(-3/10)=10/3
Then, just as we did in the earlier part we can employ the point-slope form of the line to obtain the equation of the new line. Here it is,
y=2+(10/3)(x-8)
=2+(10/3)x-(80/3)
y =(10/3)x-74/3
i dont understand it can you help
Example 1 Add 4x 4 + 3x 3 - x 2 + x + 6 and -7x 4 - 3x 3 + 8x 2 + 8x - 4 We write them one below the other as shown below.
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