Two charges eachof q=+2 micro coloumb are placed at the vertices Q and R of the triangle .the sum of sides PQ and PR is 12cm and their product is 32 cm_2 .the potential at point P is?Solution) In ΔPQR, Let PQ=8cm PR=4cmAt P, V=9*10^{9} {(2/4) + (2/8)}*10^{-6}*10^{2} = 9*10^{9}*(3/4)*10^{-4} = 6.75*10^{5}