Determine the value of resistance, Electrical Engineering

Determine the value of Resistance:

Determine the value of R, so that the condition for resonance is fulfilled

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Admittance of first branch

Y1 = 1/ R - 5 j = R - 5 j/ R2 + 25 mho

Admittance of second branch

Y2 = 1 / (4 - 3 j) = ((4 + 3 j)/25) mho

Total admittance of the circuit:

Y = Y1 + Y2 =   (R - 5 j / R2 + 25) + ((4 + 3 j)/25)

According to condition of resonance the imaginary part of the admittance must be zero i.e.

- 5/ (R2 + 25) + (3/25) = 0

     5/ (R2 + 25) = 3/25

⇒      R = 4.082 Ω

Posted Date: 2/5/2013 1:48:14 AM | Location : United States

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