Determine the total energy loss, Electrical Engineering

Determine the total energy loss:

Two capacitors C1 = 50 μF and C2 = 100 μF are connected in parallel across 250 V supply. Determine the total energy loss.

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 Total capacitance C = C1 + C2

                                    = 50 + 100 = 150 μF

Energy loss =( ½) Cv2

=( 1 /2)(150 × 10- 6 ) (250)2 = 4.687 joules

Posted Date: 2/4/2013 5:22:59 AM | Location : United States

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