Determine the acceleration of the body, Mechanical Engineering

Determine the acceleration of the body:

Two weights P and Q are associated by the arrangement shown in Figure. Neglecting friction and the inertia of the pulleys and cord, determine the acceleration of the weight Q. Suppose P = 20 kg and Q = 15 kg.


No friction is involved and hence we can assume any direction of motion. Still we can do a little more guess work. Let us suppose block P at rest, then we have 2 T = 20 × 9.81. As P is not moving, Q also shall not move, therefore we get T = 15 × 9.81 which shows that the system will have a motion, i.e. Q shall move down and P shall be moving up. The value of T shall be in between the above two values. Furthermore, it shall be clear that acceleration of P shall be half of acceleration of Q. Considering FBD for the bodies we may write for the equilibrium of Q.

We have

T + 15 a = 15 × 9.81

∴ T = 147.15 - 15 a                           ---------- (1)

Equilibrium equations for P shall give us

2 T = 20 × (a/2 ) + 20 × 9.81

= 10 a + 196.2

∴ T = 5 a + 98.1            ---------- (2)

 Considering the above two equations, we attain

T = 147.15 - 15 a = 5 a + 98.1

∴ 20 a = 49.05

a = 49.05/20  = 2.45 m / sec2

Posted Date: 1/29/2013 2:44:29 AM | Location : United States

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