Design a mod-6 synchronous counter, Computer Engineering

Design a MOD-6 synchronous counter using J-K Flip-Flops.

Ans:

Design of Mod-6 Counter:  To design the Mod-6 synchronous counter, contain six counter states (that is, from 0 to 6). For this counter, the counter design table lists the three flip-flop and their states as 0 to 6 and the 6 inputs for the 3 flip-flops. The flip-flop inputs essential to step up the counter from the now to the next state is worked out along with the help of the excitation table.  The needed counter states and the J K inputs essential for counter flip- flops are specified in the counter design table demonstrated in Table no.1.

Input pulse

 

count

Counter States

 

Flip-Flop Inputs

 

A          B          C

 

JA

 

       KA

 

JB                KB

 

JC                  KC

0

0           0          0

1             X

0                 X

0                    X

1

1           0          0

X             1

1                 X

0                    X

2

0           1          0

1             X

X                 0

0                    X

3

1           1          0

X             1

X                 1

1                    X

4

0           0          1

1             X

0                 X

X                    0

5

1           0          1

X              1

0                 X

X                    1

6(0)

0           0         0

 

 

 

Table no.1: Counters Design Table for Mod-6 Counter

 Flip-Flop A:

The primary state is 0. This change to 1 after the clock pulses. Thus, JA must be 1 and KA may be 0 or 1 (that is X). In the subsequent state 1 change to 0 after the clock pulse.  Hence, JA may be 0 or 1 (that is, X) and KA must be 1.

Flip-Flop B:

The primary state is 0 and this remains unchanged after the clock pulse. Hence, JB   must be 0 and KB may be 0 or 1 (i.e. X). In the subsequent state 0 changes to 1 after the clock pulse. Hence, JB must be 1 and KB may be 0 or 1 (that is, X).

Flip-Flop C:

The primary state is 0 and this remains unchanged after the clock pulse. Hence JC must be 0 and KC may be 0 or 1 (that is, X). In the subsequent state, this remains unchanged after the clock pulse. Thus, JC must be 0 and KC may be 0 or 1 (that is, X).The JK inputs needed for such have been found with the help of the excitation table, (as in table no.1). The flip-flop input values are entered into Karnaugh maps demonstrated in Fig. a [(i), (ii), (iii), (iv), (v) and (vi)] and a Boolean expression is determined for the inputs to the three flip-flops and then all expressions are simplified. As all the counter states have not been utilized, Xs (don't) are entered to denote un-utilized states. The expressions that simplified for each input have been demonstrated under each map. At last, these minimal expressions for the flip-flop inputs are utilized to draw a logic diagram for the counter demonstrated in fig.(b).

As before, the JK inputs needed for this have been found with the help of the excitation table, (as in table no.1). Such input values are entered in Karnaugh maps Fig. (a)[i to vi] and a Boolean expression is determined for the inputs to the three flip-flops and then all expressions are simplified. Xs have been entered in that counter states that have not been utilized. The simplified expressions for all inputs have been demonstrated under each map and at last a logic diagram based upon these expressions is drawn and is demonstrated in fig.(b).

983_Karnaugh Maps for JA,KA,JB,KB,JC,KC.png

1325_Karnaugh Maps for JA,KA,JB,KB,JC,KC1.png

Fig.(b) Karnaugh Maps for JA,KA,JB,KB,JC,KC

1472_Logic Diagram for MOD-6 Synchronous Counter.png

Fig.(c) Logic Diagram for MOD-6 Synchronous Counter

Posted Date: 5/4/2013 2:53:48 AM | Location : United States







Related Discussions:- Design a mod-6 synchronous counter, Assignment Help, Ask Question on Design a mod-6 synchronous counter, Get Answer, Expert's Help, Design a mod-6 synchronous counter Discussions

Write discussion on Design a mod-6 synchronous counter
Your posts are moderated
Related Questions
How to Calculate the Logic Circuit Outputs? Once the Boolean expression for a circuit output has been acquired, the output logic level can be determined for any set of input le

Differentiate between $display and $strobe These commands have similar syntax, and display text on screen during simulation. $display and $strobe display once every time they a

Q. Benefit of digital versatile disk read only memory? The main benefit of having CAV is that individual blocks of data can be accessed at semi-random mode. So head can be move

Why cant datareader be returned from a Web Services Method? Ans) Because datareader is not serializable.

Name the dynamic memory allocation function? Three dynamic memory allocation functions are: a) malloc, b) calloc and c) free.

Give the details of excess 3 codes and gray code using four binary digits. Ans: Table of excess 3 codes and gray code using four binary digits Binary

Disadvantages of Address translation: Disadvantages are following: A program that is too large to be held in a part needs some special design, that called overlay

External storage systems A number of different types of external memory devices are available now. Some of these are considered below (hard drives haven't been mentioned as th

Q. What is Computer communications networks? Computer communications networks are the outcome of a combination of computers and telecommunication products. An interconnected gr

Define deadlock. A process requests resources; if the resources are not available at that time, the method enters a wait state. Waiting processes might never again change state