Consider a Shiny Surface Along With Diffused Reflection coefficient
Consider a shiny surface along with diffused reflection coefficient of 0.8 and ambient reflection coefficient of 0.7, the surface has standard in the direction of 2i + 3j +4k; as several light is incident on it from the direction i + j + k hence the ambient and diffused intensities are of order 2 and 3 units. Find out the intensity or reflected light.
Solution: The combined consequence of ambient and diffused reflection is specified by:
I = I_{a} K_{a} + I_{d} K_{d} cos θ = I_{a} K_{a} + I_{d }K_{d} ( N¯ .L¯)
By using the data specified in the equation we find:
I = 2 * 0.7 + 3 * 0.8 * ((2i + 3j + 4k).(i +j +k))
= 1.4 + 2.4 (2 + 3 + 4)
= 1.4 + 9*2.4
= 23