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Compute the outside diameter of the shaft:
A hollow shaft of diameter ratio is 0.4 is needed to transit 600 kW at 120 rpm. The maximum torque being 20% greater than the mean torque. The shear stress is restricted to 60 N/mm2 and the lowest of 0.01 radians per unit length. Compute the outside diameter of the shaft. Take G = 0.8 × 105 N/mm2.
di / do = 0.4
di = 0.4 do
R = do/ 2
P = 600 kN, N = 120 rpm, P = 2π NT /60
600 × 103 =( 2π× 120T )/60
∴ T = 47.7 × 103 N-m
Tmax = 1.2 T = 1.2 × 47.7 × 103 = 57.3 × 103 N-m
τmax = 60 N/mm2 = 60 × 106 N/m2
Tmax = τmax × Z P
⇒ 57.3 × 103 = 60 × 106 × 0.19
∴ do = 0.17 m
Tmax / J = G θ/ l
∴ do = 0.165 m
∴ do = 0.17 m = 170 mm
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