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A: no, can't.
The names of, precedence of, associativity of, and arity of operators is fixed through the language. In C++, there is no operator** so you cannot create one for a class type.
If you have a doubt, assume that x ** y is the same as x * (*y) (in other terms, the compiler suppose y is a pointer). As well, operator overloading is only syntactic sugar for function calls. Although this specific syntactic sugar can be very sweet, it doesn't add anything fundamental. I recommend you overload pow (base,exponent) (double precision version is in ).
By the way, operator^ can work for to-the-power-of, except it contain the wrong associatively and precedence.
It is a class defined in the scope of a function _ any function, whether a member functions or a free function. For instance: // Example : Local class // int f() { c
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