Calculations for the force to move a block, Mechanical Engineering

Calculations for the force to move a block:

Two blocks A and B having weight 4KN and 2KN respectively are in equilibrium position as shown in the figure given below. Coefficient of friction for both the surfaces is same as 0.25, make calculations for the force P which is required to move the block A.

1424_Calculations for the force to move a block1.png

Sol.: Considering equilibrium of the block B. Resolving force along with the horizontal and vertical directions:

 

2306_Calculations for the force to move a block2.png

 

Tcos30° -µRb = 0;

Tcos30° = µRb                                     ...(i)

Rb + Tsin30° - Wb = 0;

Tsin30° = Wb - Rb               ...(ii)

By dividing equation (i) and (ii), We get

tan30° = (Wb  - Rb)/µRb

0.5773 = (2- Rb)/0.25Rb;

0.1443Rb = 2- Rb

Rb = 1.748N

Fb = µRb = 0.25 × 1.748 = 0.437N

Considering equilibrium of block A: Resolving forces along horizontal and vertical directions,

1925_Calculations for the force to move a block.png

Posted Date: 10/17/2012 7:04:00 AM | Location : United States







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