By what percentage should the pressure of a given mass of gas be increased,so as to decrease its volume by 10% at a constant temperature.
P1V1/T1=P2V2/T2
BUT TEMP. REMAINS CONSTANT.
SO P1V1=P2V2
OR P1V1=P2(V1-V1/10)
OR P1V1=P2*9V1/10
OR P1=9P2/10
OR P2=10P1/9
NOW, PERCENTAGE INCREASE=(P2-P1)*100/P1
WHICH IS EQUAL TO 100/9%