Calculate generated emf, copper losses and efficiency., Electrical Engineering

Q. A shunt generator gives full load output of 30 kW at a terminal voltage of 200V. The armature and field resistance are 0.05? and 50? resp.. The iron and friction losses are 1000 W. Calculate

   (1) generated emf      (2) copper losses    (3) efficiency

Ans.

 

Given

                                V = 200 V, P = 30 × 103 W,Ra = 0.05 W, Rsh = 50 W

 

                             Pi+f = 1000 W

 

                                  I = P/V = 30 × 103/200 = 150 Amp

 

                                 Ish = V/Rsh = 200/50 = 4A

 

                                 Ia = I +Ish = 150 + 4 = 154 Amp

 

       (a)                      E = V + Ia Ra = 200 + 154 × 0.05 = 207.7 volt

 

       (b)                     Copper losses = Ia2 Ra + Iash Rsh

 

                                                        = (154)2 × 0.05 + (4)2 × 50 = 1985.8w

(c)                   Efficiency ? = Output/ Output + Copper losses + iron losses + friction loss 

 

                   = 30 × 103/30 × 103 + 1985.8 + 1000 = 90.95%

 

Posted Date: 7/23/2012 1:39:43 AM | Location : United States







Related Discussions:- Calculate generated emf, copper losses and efficiency., Assignment Help, Ask Question on Calculate generated emf, copper losses and efficiency., Get Answer, Expert's Help, Calculate generated emf, copper losses and efficiency. Discussions

Write discussion on Calculate generated emf, copper losses and efficiency.
Your posts are moderated
Related Questions
Using Bode plot calculate (a) Phase margin (b) Gain margin (c) Stability of closed loop system. The open transfer function of the system is t=30/(s+2)/(s+3)Using Bode plot calcula

Q. A six-pole, double-layer dc armature winding in 28 slots has five turns per coil. If the field flux is 0.025 Wb per pole and the speed of the rotor is 1200 r/min, find the value

what is fuck

#qConsider a point-to-point radio link between two highly directional antennas in a stationary environment. The antennas have antenna gains of 30 dB, distance attenuation is 150 dB

Operation of MOSFET The operation of a metal-oxide-semiconductor field-effect transistor which is abbreviated as MOSFET can be separated into three modes, depending upon the

Types of Meter Test A meter should pass the subsequent two types of tests: Type Tests Routine Tests Meters are calibrated such in which the whole

Q. Illustrate working of Direct-coupled Amplifiers? Direct-coupled Amplifiers : The following figure shows a direct-coupled amplifier consisting of two stages. A dc voltage i

block diagram of digital control system and explain each block

Q. What the major advantages FET transistors over BJT transistors? a. BJT transistor (bipolar junction transistor) is a bipolar device - the prefix bi-revealing that the conduc

Question: a) Describe five advantages of LED lighting over conventional incandescent lighting. b) State two impairments that reduces the radiant flux of a surface-emitting