Calculate diameter of shaft in maximum direct stress, Mechanical Engineering

Calculate diameter of shaft in maximum direct stress:

A shaft is designed for transmitting 100 kW power at 150 rotation per minute. Shaft is supported in bearings 3 m apart and at 1 m from 1 bearing a pulley exerting transverse load of 30 KN on shaft is mounted. Obtain diameter of shaft if maximum direct stress is not to exceed 100 N/mm2.               


Ra + Rb = 30 KN

Ra = 20 KN

Rb = 10 KN

Maximum bending moment occurs at 'C'.

MC  = 20 × 1 = 20 KN-m                                                                                ...(i)

The power transmitted by shaft P = 2  NT/60

100 × 103  =   2  x 150. T/60

T = 6366.19 N-m                                                                                         ...(ii)

Equivalent bending moment Me = ½[M + (M2 + T2)1/2]

= ½[20,000 + (20,0002 + 63692)1/2]

Me  = 20494.38 N-m                                                                                      ...(iii)

1787_Calculate diameter of shaft in maximum direct stress.png

From the bending equation Me/I = σ/y 2044.38 × 103/[ ( ?/64)d4] 100/d/2

d = 127.8 mm 

Posted Date: 10/27/2012 1:38:15 AM | Location : United States

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