The Null Hypothesis - H0: β0_{ }= 0, H0: β_{1 }= 0, H0: β_{2 }= 0, Β_{i }= 0
The Alternative Hypothesis - H1: β0_{ }≠ 0, H0: β_{1 }≠ 0, H0: β_{2 }≠ 0, Β_{i }≠ 0 _{i =0, 1, 2, 3}
Reject H0 if |t | > t?¹ = 1.96153 or Reject H0 when P-value ≤ α = 0.05
Predictor Coef SE Coef T P VIF
Constant 0.37794 0.01369 27.61 0.000
totexp -0.00119745 0.00006058 -19.77 0.000 1.272
income -0.00007625 0.00004302 -1.77 0.077 1.282
age 0.0016660 0.0003076 5.42 0.000 1.062
nk 0.029515 0.004765 6.19 0.000 1.005
Inverse Cumulative Distribution Function
Student's t distribution with 1514 DF
P( X <= x ) x
0.975 1.96153
Since the constant = 27.61 > 1.96153 (CV) and the P-Value is ≤ α = 0.05, H0 would be rejected as there is sufficient evidence.
Since the totexp = -19.77 < 1.96153 (CV) and the P-Value is ≤ α = 0.05, there is evidence to suggest that H0 should be accepted according to the T value however the P-Value suggest otherwise but it is not significant.
Since the income = -1.77 < 1.96153 (CV) and the P-Value is ≤ α = 0.05, there is evidence to suggest that H0 should be accepted according to the T value however the P-Value suggest otherwise but it is not significant.
Since the age = 5.42 > 1.96153 (CV) and the P-Value is ≤ α = 0.05, H0 would be rejected as there is sufficient evidence.
Since the nk = 6.19 > 1.96153 (CV) and the P-Value is ≤ α = 0.05, H0 would be rejected as there is sufficient evidence.