Each of the series 3+5+7+..... and 4+7+10.......... is continued to 100 terms find how many terms are identical.Ans) 48 terms would be common to both the series...first take common terms in both series..7, 13,.....so,this has a common difference of 4 starting with 7.now last term of the given series are 201 and 301 respectively..So we can end our calculation by checking upto 201.201=7+(n-1)4----->n=48(we have to take integer nearest to it)