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If roots of (x-p)(x-q) = c are a and b what will be the roots of (x-a)(x-b) = -c    please explain? Ans) (x-p)(x-q)=c x2-(p+q)x-c=0 hence,   a+b=p+q  and      a.b=pq-c

Determination of the Regression Equation The determination of the regression equation such given above is generally done by using a technique termed as "the method of least sq

1/a+b+x  =1/a+1/b+1/x    a+b ≠ 0 Ans: 1/a+b+x  =1/a+1/b+1/x => 1/a+b+x -1/x = +1/a +1/b ⇒  x - ( a + b + x )/ x ( a + b + x )   = + a + b/ ab ⇒

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