1-Phase Full Bridge inverter will RL Load
For a resistive load R the load current wave form will be identical with load voltage wave form and feedback diodes will not come into conduction. In the case of RL -Load the wave form of output current is shown in the circuit of 1-? full bridge inverter with R_{l} load is shown .
Before t =0 thyristors T_{3} and T_{4} are conducting and load current is flowing in negative direction. After T_{3} and T_{4 } are turned of at t=0 load current io can not change its direction immediately due to the existence of inductance in the load. Therefore after t= 0 diodes D_{1} and D_{2} start conducting and allow the load current to flow against the source voltage. Load voltage becomes V_{dc}.
At t=0 thyristor T_{1} and T_{2} are gated but these thyristors will not turn on because these are reverse biased by voltage drops across D_{1} and D2. After the load current becomes equal to zero T_{1} and T_{2 } start concocting up to the period t = T/2 now load current start flowing in positive direction ( as we assumed in circuit) at t= T/2 T_{1} and T_{2} are commutated and T_{3} and T_{4} are gated but tagging the current can not change its direction immediately. As a result diodes D_{3} and D4 starts conducting to allow the current to flow in positive direction. Thyristors T_{3} and T4 will not start conduction until the load current through diodes D_{3} and D_{4} falls to zero because these thyristors will not turn on as these are reverse biased by the voltage drops in the D_{3} and