A stone drops from the edge of the roof. It passes the window 2 m high in 0.1s . How far is the roof above the top of the window?
Height of the window (h) = 2mAcceleration due to gravity g = 9.8 m/s2Time taken (t) = 0.1 sThe velocity of the stone when it reaches the top of the window is to be calculated.
Applying the II equation of motion,h=ut+1/2 at^22=0.1u+0.0490.1u=1.951u= 19.51m/sThus, the velocity 19.51 m/s will be the final velocity of the stone when it is covering the distance between the roof and the window.Initially the stone is at rest i.e., u = 0v^2-u^2=2gh(19.51)^2=19.6h=> h= 19.42mDistance between the roof and the window =19.42 m.