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A time and motion expert is interested in comparing two new methods of completing a certain task. The participants are divided into two groups of equal size and, for each group, their times (in minutes) to completion of the task will be monitored. It is anticipated that the completion times for each group will have a range of 10 minutes. If an estimate of the difference in mean time to completion of the task is recognized to be within ±2 minutes with 95% reliability, how large of a sample is needed (for each group)? What is the sampling assumption being made?
An advertising agency that serves a major radio station wants estimate the mean amount of time that the station's audience spends listening to the radio daily.
Standard deviation of 12%. Assume that scores in both classes follow a normal distribution. Convert Maria's midterm score of 84 to a standard z score.
calculate the variance and the standard deviation of this probability distribution?calculate the expected rate of
beechwood specialty electronics has just leased space for a store in the crestview hills towne center that will provide
A random sample of 20 one-way fares during particular month had a mean of $210 with a standard deviation of $43. At 0.02, is there sufficient evidence to conclude a difference from the stated mean?
Determine the shape of chi-square distribution?
suppose the results of the analyses in problem 15-17 are reported and criticized because the participants were not
an experiment involves selecting a random sample of 256 middle managers at a random for study. one item of interest is
The company believes that the price elasticity for this product is about -2.5. If it decreases its price to $63, what should be the quantity sold? Will the revenue increase? Why
Mean of 29.44 with a standard deviation of 2.86. Conduct a two tailed hypothesis test at a significance level of .05 to see if the two means are different.
the life times y in years of a certain brand of low-grade lightbulbs follow an exponential distribution with a mean of
the claim is the proportion of peas with yellow pods is equal to 0.25 or 25. the sample statistics from one experiment
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