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What is the formula used to get percentile from z-score? I have z-scores but am using excel and want to be able to type in a formula to figure percent instead of coming here and continuing to figure it out.
Below is the number of new cars sold at Sharkey in the last seven months and for the last eight months at Dave White. Do you agree with Mr. Sharkey? Use the .01 significance level."
One-way random effects model : yi j = + i + i j , i j "s are independent error terms with N(0, 2 ), i are independent N(0, 2 ), And i and i j are independent Why?
In a test of the independence of two variables, one the variables has two possible categories and the other has three possible categories.
The null hypothesis is the alternative is Use the given sample data to find out the P-value for the hypothesis test. Provide an interpretation of the P-value.
Based on the numbers presented, what do you think of the discrimination claim?
Suppose that we generate a random sample from a given dis- tribution. If it is desired that the probability that the sample mean will be within 2 standard deviations of the mean of the distribution is at least .99, how large should the sample size..
What is the probability of at least three hacker attempts during a month? What is the probability of a hacker attempt occurring every 15 days or less (assume a 30 day month).
For a normal random variable X with mean 70 and standard deviation 10. Calculate the probability that 60 80}.
How large a sample must one take to be 90% confident that the estimate is within 0.05 of the true proportion of women over 55 who are widows?
When using the normal distribution (empirical rule) to obtain the bounds for 99.73 percent of the value in a population, the interval generally will be ______the interval obtained for the same percentage if Chebyshev's theorem is assumed., shorter..
In 1851 there were 25,466 nurses in Great Britain. Find the probability that a British nurse selected at random in 1851 would be 60 years or older. (My guess is The sum of the percent of nurses 60 years are older are added equaling 36% or 1967.76/2..
difference between the population proportions. You may assume the samples are independent. Which of the following gives the justification for normality in this situation?
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