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Problem- A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ?C. The initial concentrations of Pb2+ and Cu2+ are 5.10×10?2M and 1.50M , respectively.
1) What is the cell potential when the concentration of Cu2+ has fallen to 0.220M ?
2) What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.350V ?
How do I fix this show all steps to describe the solution of above problem?
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