Reference no: EM13748948

TypeofArray nameOfArray [theSizeOfArray];

For instance,

int studentMark [10];

The above array is a declaration of an array of type integer. The name of the array is studentMark, and the array is of size 10.

Arrays in C can be initialized by using a single statement that declares the array or by breaking it into two statements. In the first instance, the above array will appear as follows:

int studentMark [10] = {10, 20, 30, 40, 50, 60, 70, 80, 90, 99};

Alternatively,

int studentMark [10];

studentMark [0] =10;

studentMark [1] =20;

An example illustrating all of the concepts above is as follows,

/* program that prints out five numbers */

#include <stdio.h>

int main ()

{

int numbers[5];

int m, n;

/*initializing array elements */

for (m =0; m<= 5; m++){

numbers[m] =m;

}

/*outputting the values in an array */

for (n =0; n <=5; n++)

{

printf ("Number [%d] =%dn", n, numbers[n]);

}

return 0;

}

}

The output from the code above appears below,

Number [0] =1;

Number [0] =2;

Number [0] =3;

Number [0] =4;

Number [0] =5;


Did you intend for your array to over write the values, it looks as though it wrote all of the numbers to the same element [0], or am I reading it wrong, which is highly possible.