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A 56-question multiple choice test has 4 possible answers for each question and a student chooses the answers to each problem at random. A student selects 16 correct answers. Find the probability of the result using the normal curve approximation to the binomial distribution.
No, there is not sufficient information to reject the hypothesis that the proportion of cats and the proportion of dogs that sleep more than 10 hours per day are the same because the test value -0.65 is inside the acceptance region (-1.96,1.96).
the maximum point total for the quarter was 200. The point totals for the 10 students are given in the stemplot below. For the density curve displayed below, which of the following is true?
You might find the probabilities using the Table or software of your choice. Please explain how you obtained your results.
As part of a safety check, the Keystone Cops randomly stopped 65 ambulances and checked their tire pressure. The sample mean was 32 lbs/sq. in. with a sample standard deviation of 2 lbs/sq. in. Find the 98% confidence interval for the population m..
Use Random Number Generation (RNG) in Analysis ToolPak of Excel to generate n = 5 observations from the Normal distribution N(20, 5). Construct the 95% confidence interval for μ.
As it is a 2 _ 2 table, try also two-tailed two-sample z test for ð1 = ð2 and verify that z2 is same as your chi-square statistic. Which test do you favour? Describe why?
For a population with a mean of μ = 50 and a standard deviation of σ = 10, how much error, on average, would you expect between the sample mean (M) and population mean for:
What is the probability that a visually impaired student gets less than 6.9 hours of sleep?
Calculate a value of lambda using the data from last week concerning the news networks and the reporting practices. Compare your resulting lambda to the resulting chi-square from last week.
Compute the within group variability. Do you require any post hoc testing? Why or why not? Decribe in detail.
What is the point estimate of the proportion of the population of employees who strongly dislike their current work experience (to 2 decimals)?
You had calculated the following measures of central tendency: the mean, the median, and the mean trimmed 25%. Which of these measures of central tendency will change when you correct the recording error?
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