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For the Module 1 discussion you looked for a ridiculous product. In this second installment of "What were they thinking?!?!" go to YouTube and find the most ridiculous advertisement that you can. Remember that most advertisements you currently see on TV are also on YouTube, including even some old commercials that you saw on TV when you were kid.
Share the link to the ridiculous commercial with your classmates and explain why you found it ridiculous. But no matter how ridiculous the advertisement seems, remember that a lot of money was likely spent developing and producing it. So try your best to explain what the advertising geniuses at this company were thinking when they came up with this advertising campaign, and use the terminology and concepts from the background materials in your answer.
As an extra incentive to find the most ridiculous advertisement, we will have a contest to see which one of you can find the very most ridiculous one. In one of your posts vote for the most ridiculous video that any of your classmates posted (you can't vote for your own one).
according to an almanac 60 of adult smokers started smoking before turning 18 years olda compute the mean and standard
Use the population standard deviation along with the sample mean, S, and find a 92% confidence interval for the population mean. Is the true population mean contained in this interval?
suppose the time to prepare a bed at a hospital is modeled with a random variable with a mean of 20 mins and a variance
Compute the Expected Value (Mean), The Variance, and The Standard Deviation for this random variable. X 1 2 3 4 5 6 7
Prepare a table showing sales, a time trend, and dummy variables to take into account seasonal effects. (b) Using the data from the table in part
A histogram of time spent eating & drinking each day is skewed right. Use this result to explain why a large sample size is needed to construct a confidence interval for the mean time spent eating & drinking each day.
Construct a 95 percent confidence interval for the true mean.
When we carry out a goodness of fit chi-square test, the expected frequencies are based on the alternative hypothesis
The mean is 75 and the standard deviation is 6. If 1200 students took the test, approx how many students would be expected to score between 69 and 81?
prove that the velocity induced region surrounding a doubly infinite vortex sheet of constant strength satisfies the
Study About The Current Parking Policy Opposed by Nurses
Is the normal distribution (or its special case, the standard normal distribution) effective in characterizing situations and/or in helping managers make decisions?
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