### Horizontal velocity of the aircraft

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##### Reference no: EM13857249

X = (3000 + a*100),
M = (75 + c) Kg
Cd = 0.5 (skydiver) (Area 0.4m2)
Cd = 1.2 (parachute) (Area 40m2)

A sky diver, weighing M Kg, jumps from a moving aircraft at X meters above the ground. He/She initially free-falls for a period of seconds then deploys a parachute to to allow him/her to land at a safe speed of under 6 m/s.

The sky diver uses a spread-eagle position during freefall that maximises their drag coefficient , Cd. (Cd based on frontal area of 0.5m2)

Full parachute deployment takes 5 seconds and during this period the drag coefficient of the parachute can be assumed to vary linearly between 0 and the final value needed for a safe descent speed.

Using whatever numerical techniques appropriate determine a velocity versus time graph of his/her descent. Estimate the amount of free fall time that would be possible that would still allow full deployment of the parachute and a safe landing.

Ignore any initial horizontal velocity of the aircraft and wind or atmospheric turbulence conditions.

Attachment:- Assignment (2).pdf

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