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The test scores of 6 randomly picked students and the numbers of hours they prepared are as follows:
Hours: 5 10 4 6 10 9Score: 64 86 69 86 59 87
The equation of the regression line is y(^on top)=1.06604x+67.3491. Find the coefficient of determination.
Each with n = 6 participants. Compute the pooled variance and the estimated standard error for the mean difference. (Use 3 decimal places.)
This problem involves calculating and interpreting the 95% confidence interval for a proportion. While you can use SPSS to determine proportions, you need to calculate the confidence interval by hand.
Roll a balanced 8-sided die and a balanced 6-sided die and add the spots on the up-faces. Call the sum X. What is the probability distribution of the random variable X?
An old saying in golf is "you drive for show and you putt for dough." The point is that good putting is more important than long driving for shooting low scores and hence winning money.
Calculate the 95% confidence interval for the population proportion of patients who are successfully treated. (c) Write a sentence that correctly interprets this interval.
Conversely with the ball from the second urn. Let Xn denote the state of the system after the nth step. Calculate its transition probability matrix.
Find a 99% confidence interval for the population mean number of weekly miles.
Complete the ANOVA table. Carry out a test of hypothesis on each of regression coefficients. Could you delete any of the variables?
In the survey of 8000 women, 5431 say they change their nail polish once the week. Create the 99% confidence interval for population proportion of women who change their nail polish once a week.
Estimate the percentage who weigh more than 180 pounds? Assume that we want 96% confidence that the error is no more than 1.5 percentage points.
In order to control costs, a company wishes to study the amount of money its sales force spends entertaining clients. Compute and interpret the Z score for each of the six entertainment expenses.
When comparing data from different distributions, what is the benefit of transforming data from these distributions to conform to the standard distribution?
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