Explain what would be the ratio of the unprotonated

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Uric acid dissociates as exposed in the figure at the right with a pKa of 5.80 as well as can be treated as a simple monoprotic acid in this pH range. Its solubility in urine depends on the relative amount of protonated as well as unprotonated forms. A urine sample was found to have a pH of 5.35.

Explain what would be the ratio of the unprotonated form, A- to the protonated form, HA for uric acid in this urine sample?

Reference no: EM13679652

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