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2.50 mol NOCl was placed in a 2.50 L reaction vessel at 400ºC. After equilibrium was established, it was found that 28% of the NOCl had dissociated according to the equation
2NOCl(g) 2NO(g) + Cl2(g).
Calculate the equilibrium constant, Kc, for the reaction.
Step 1: 2.50mol / 2.50L = 1.0M
Step 2: 1.0-28%=0.72
After that I'm not sure what to do.
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