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Question- A soluble fertiliser contains phosphorus in the form of phosphate ions (PO43-, 95.0 g/mol). To determine the PO43- content by gravimetric analysis, 3.46 g of the fertiliser powder was completely dissolved in water to make a volume of 244 mL. A 43.3 mL volume of this solution was pipetted into a conical flask and the PO43- ions in the solution were precipitated as MgNH4PO4. The precipitate was filtered, washed with water and then converted by heating into Mg2P2O7. The mass of Mg2P2O7 (222.6 g/mol) was 0.059 g.
Anyone can tell me how to solve it step by step so that I will be able to understand what is going on?
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