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1. A beverage dispensing machine is calibrated so that the amount of beverage dispensed is approximately normally distributed with a population standard deviation of 0.15 deciliters.Construct a 90% confidence interval for the population mean amount of beverage dispensed by this machine based on a random sample of 36 drinks dispensing an average of 2.25 dl. Show all steps as given in the class handout.
2. Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma. Over a period of months, an adult male patient has taken eight blood tests for uric acid. The mean concentration was 5.35mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with population standard deviation 1.85mg/dl. Construct a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. Show all steps as given in the class handout.
A researcher wants to see if urban, suburban and rural communities differ in terms of the support for food banks. The researcher randomly chose 4000 food banks from around t
Given f(x) = 0.1 for 10 ≤x≤20. The mean of the distribution is 15 and the standard deviation is 2.89. Find the probability that x falls between 12 and 15.
Draw a picture of the sampling distribution of H, the highest number each day, and compare it to the equivalent picture for the Cash 5 game, shown in Figure. Do you expect t
Find the linear correlation coefficient r for the following: x: 2, 3, 4, 7, 7 and y: 9, 2, 5, 1, 1. Find the y-intercept of the following: x: 1, 3, 5, 8, 9 and y: 4, 2, 6, 6,
Jen will call Cathy on Saturday with a 60% probability. She will call Cathy on Sunday with an 80% probability. The probability that she will call on neither of the two days
A pharmaceutical company wants o test a new cholesterol drug. The average cholesterol of the target population is 200 mg and they have a standard deviation of 25 mg. The co
In a sample of 250 recent applicants, 130 passed on their first attempt. At the 0.05 level of significance, can we conclude that the proportion passing on the first try has
The survey reported that 31% of the respondents feel they have to save more for retirement to make up for what they lost. Develop a 95% confidence interval for the populatio
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