Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Joan's nursery specializes in custom-designed landscaping for residential areas. the estimated labour cost associated with a particular landscaping proposal is based on the number of plantings of trees,shrubs and so on to be used for the project. for cost-estimated purposes, managers use two hours of labour time for the planting of a medium sized tree. actual times from a sample of ten plantings during the past month follow (times in hours)
1.7 1.5 2.6 2.22.4 2.32.6 3.0 1.42.3
with a 0.05 level of significance, test to see whether the mean tree-planting time differs from two hours.
1) state the null and alternative hypothesis
2) compute the sample mean
3) compute the sample standard deviation
4) compute the sample (test) statistic
5) formulate the decision rule
6) what is your conclusion
For the following situation, assume the random variable is normally distributed and use a normal distribution or a t-distribution to construct a 90% confidence interval for the population mean. If convenient, use technology to construct the confid..
Find the sample size for the 95% confidence interval used to estimate the population proportion.
What is the major difference between finding significance and confidence intervals using population samples or using population proportions?
Determine probability of generating six digits and getting code consisting of 1, 2, 3, ..., 6 if each digit can be repeated?
The regression line yˆ2 = 3 + 2x has been fitted to the data points (4,8), (2,5), and (1,2). The residual sum of squares will be:
Do not forget to test for any applicable difference in means (Tukey implies).
How many subjects would you approximately need to reduce the length of the 95% confidence interval to 2 units?
In a random sample of 53 concrete specimens, the average porosity (in percent) was 21.6 and the standard deviation was 3.2. a) Find a 90% confidence interval for the mean porosity of specimens of this type of concrete.
The data below are the numbers of hours of homework done as reported by 24 high school juniors for the last week in September 2006.
The average stock price for companies making up the S&P 500 is $40, and the standard deviation is $10. Assume the stock prices are normally distributed. What is the probability a company will have a stock price less than $33.
Generate a relative frequency histogram using ten-point intervals to show the distribution of the scores.
Either use the p-value approach to hypothesis testing or use the significance level approach with α = .05.
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd