Compute the amount naoh that is acetic acid

Reference no: EM13313349

Calculate the amount (in mL) of a 1.520M NaOH that is required to add the following acetic acid solutions to prepare a buffer with the corresponding pH: pKa of acetic acid = 4.74 (a) 30.00mL of a 5.00% (w/v%) acetic acid; the resulting acetate buffer has a pH of 5.75 (b) 50.00mL of a 5.00% (w/v%) acetic acid; the resulting acetate buffer has a pH of 4.98 (c) 40.00mL of a 5.00% (w/v%) acetic acid; the resulting acetate buffer has a pH of 4.33 The mole of NaOH in the equilibrium table is a function of volume (i.e. MNaOH×V) and it will be the limiting reagent in the equilibrium table. I know I'm supposed to Set up an equilibrium table for a reaction between acetic acid and NaOH and then use the Henderson-Hasselbalch equation to determine the volume of NaOH (i.e. V) that is required to prepare the specific acetate buffer solution at the corresponding pH.

Reference no: EM13313349

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