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Twenty subscribers were surveyed, it found that the annual health insurance premiums for a family with coverage through an employer averaged $10,979.00. The standard deviation of the sample was $1000.00.
a. based on this sample information, develop a 90% confidence interval for the population mean yearly premium.
b. How large a sample is needed to find the population mean within $250 at 99% confidence?
At 95% level of confidence, can we conclude that the babies using the Gibbs product gained less weight?
The probabilities of low, medium and high compliance are 0.3, 0.4, and 0.3, respectively
According to a recent survey, 275 of 400 middle-aged Americans said they used the Internet regularly. 140 of 400 senior citizens said they used the Internet regularly.
Graph the distribution using a histogram. Calculate the mean and standard deviation.
How can we be certain that surveys and statistics that we hear about in the media are accurate samples and unbiased? Is there a way to dissect the information and determine if a probability sample was used?
Based on these data, explain whether or not course attendance had any effect on determining of a restaurants violation of health code.
Mark makes it a policy not to buy bananas unless the price is 33 cents or less per pound. What proportion of the time would he buy bananas?
Probability using Pareto chart - Evaluate the probability of randomly selecting an adult from the sample who doesn't always eat healthy foods because he or she has no time to cook or is confused about nutrition.
Soft Drinks a vending machine automatically pours soft drinks into cups. As the amount of soft drink dispensed into a cup is normally distributed
The formula for a 95% confidence interval yields the interval 640 ± 5.88. Find out whether each of the given statements is true or false.
prevent coronary artery vasoconstriction and the attendant reduction in blood flow to the heart and mechanical function.
What is the expected number of crimes that will be solved? What is the standard deviation?
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