+1-415-670-9521

info@expertsmind.com

# Current Magnetic Effects Assignment Help

###
Electromagnetism - Current Magnetic Effects

**Current Magnetic Effects**

Magnetic field strength due to a straight finite current carrying conductor

**B = μ**_{0}I/4πrd [cos∅^{2}] = μ_{0} I/4πd [sin α - sin β]

The direction of magnetic field is given by right hand thumb rule.

Magnetic field at perpendicular bisector of a current carrying conductor

**B = μ**_{0} Ia/2πd a^{2} + 4d^{2}

Magnetic field due to a long straight conductor

**B = μ**_{0}I/2πd

Force between parallel conductors

**dF/dl = μ**_{0} l_{1}l_{2}/2πd

The force is attractive if the currents are in the same direction and repulsive if the currents are in the opposite direction.

Magnetic field at the centre of a circular loop carrying current

The direction is perpendicular inwards if the current is clockwise and perpendicular outwards to the plane of paper if the current is anticlockwise.

Magnetic fields due to a circular are of radius r at the centre p

**B = μ**_{0} I (α)/4π

Take **α** in radian

For a semicircular loop **α = π**^{2}

**B = μ**_{0}I/4r

Magnetic field at any point on axial line

**B = μ**_{0} Ir^{2}/2 (r^{2} + x^{2}) ^{3/2}

Find the direction as for a circular coil.

Special case magnetic field at the centre **(put x = 0)**

**B = μ**_{0}I/2r

Ampere circuital law

**?B dl = μ**_{0}l

Magnetic field due to a long solenoid at the axis of a solenoid

**B = nμ**_{0}l

Where n is number of turns per unit length

Magnetic force between tow current carrying conductors (long)

**dF/dl = μ**_{0} l_{1}l_{2}/(2πd)

The force is attractive if currents are in same direction and repulsive if currents are in opposite directions.

Magnetic field at any point p in the solenoid

**Bp = 1/2 μ**_{0}nl (cos θ_{i} - cos θ_{2})

At point, f or E due to a long solenoid

B = 1/2 μ_{0}nI

Magnetic field at any point p (acting tangentially) on a toroid

**B = μ**_{0}N_{i}/2π

Where N = total number of turns

Magnetic field due to a moving charge

**B = μ**_{0}qv sin∅/4π^{2} B = μ_{0}q v x r/4πr^{3}

Magnetic force between moving charges

**F mag = μ**_{0}q_{1}q_{2} (v_{1}v_{2}/4π^{2})

If the charges are like and move in same direction that they repel each other because F elec > F mag which is repulsive though magnetic force is attractive.

The force will be attractive only if the charges are of opposite nature.

ExpertsMind.com - Current Magnetic Effects Assignment Help, Current Magnetic Effects Homework Help, Current Magnetic Effects Assignment Tutors, Current Magnetic Effects Solutions, Current Magnetic Effects Answers, Electromagnetism Assignment Tutors

**Current Magnetic Effects**

**B = μ**

_{0}I/4πrd [cos∅^{2}] = μ_{0}I/4πd [sin α - sin β]The direction of magnetic field is given by right hand thumb rule.

Magnetic field at perpendicular bisector of a current carrying conductor

**B = μ**

_{0}Ia/2πd a^{2}+ 4d^{2}

Magnetic field due to a long straight conductor

**B = μ**

_{0}I/2πdForce between parallel conductors

**dF/dl = μ**

_{0}l_{1}l_{2}/2πdThe force is attractive if the currents are in the same direction and repulsive if the currents are in the opposite direction.

Magnetic field at the centre of a circular loop carrying current

The direction is perpendicular inwards if the current is clockwise and perpendicular outwards to the plane of paper if the current is anticlockwise.

Magnetic fields due to a circular are of radius r at the centre p

**B = μ**

_{0}I (α)/4πTake

**α**in radian

For a semicircular loop

**α = π**

^{2}

**B = μ**

_{0}I/4rMagnetic field at any point on axial line

**B = μ**

_{0}Ir^{2}/2 (r^{2}+ x^{2})^{3/2}

Find the direction as for a circular coil.

Special case magnetic field at the centre

**(put x = 0)**

**B = μ**

_{0}I/2rAmpere circuital law

**?B dl = μ**

_{0}lMagnetic field due to a long solenoid at the axis of a solenoid

**B = nμ**

_{0}lWhere n is number of turns per unit length

Magnetic force between tow current carrying conductors (long)

**dF/dl = μ**

_{0}l_{1}l_{2}/(2πd)The force is attractive if currents are in same direction and repulsive if currents are in opposite directions.

Magnetic field at any point p in the solenoid

**Bp = 1/2 μ**

_{0}nl (cos θ_{i}- cos θ_{2})At point, f or E due to a long solenoid

B = 1/2 μ

B = 1/2 μ

_{0}nIMagnetic field at any point p (acting tangentially) on a toroid

**B = μ**

_{0}N_{i}/2πWhere N = total number of turns

Magnetic field due to a moving charge

**B = μ**

_{0}qv sin∅/4π^{2}B = μ_{0}q v x r/4πr^{3}Magnetic force between moving charges

**F mag = μ**

_{0}q_{1}q_{2}(v_{1}v_{2}/4π^{2})If the charges are like and move in same direction that they repel each other because F elec > F mag which is repulsive though magnetic force is attractive.

The force will be attractive only if the charges are of opposite nature.

ExpertsMind.com - Current Magnetic Effects Assignment Help, Current Magnetic Effects Homework Help, Current Magnetic Effects Assignment Tutors, Current Magnetic Effects Solutions, Current Magnetic Effects Answers, Electromagnetism Assignment Tutors